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X^2+231-32X=0
a = 1; b = -32; c = +231;
Δ = b2-4ac
Δ = -322-4·1·231
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-10}{2*1}=\frac{22}{2} =11 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+10}{2*1}=\frac{42}{2} =21 $
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